
How do I differentiate $\sin^2x$? - Mathematics Stack Exchange
Jan 25, 2014 · I thought that because this is true: $$ \sin^2x= (\sin x)^2,$$ I could differentiate the expression like this: $$ \frac {d} {dx}\sin^2x=2\cos x.$$ But I am supposed to get $$ \sin (2x) …
calculus - Definition of a derivative of sine squared x.
Dec 9, 2012 · Definition of a derivative of sine squared x. Ask Question Asked 13 years ago Modified 12 years, 9 months ago
calculus - Why does the derivative of $\sin^2x$ need the chain …
Nov 17, 2018 · Why does the derivative of $\sin^2x$ need the chain rule? Isn't it just $2\sin x$ by the power rule? Ask Question Asked 7 years, 1 month ago Modified 7 years, 1 month ago
calculus - Derivative of $\sin (x^2)$ using first principle ...
Dec 4, 2016 · 0 I am able to find derivatives of $\sin x$ and $\sin 2x$ using first principle (Using the formula for $\sin (A)-\sin (B)$ and subsequently using $\lim_ {x\rightarrow 0}$ $\frac {\sin x} …
What is the derivative of $y=\sqrt {\frac {1- \sin (x)} {1+\sin (x)}}$
Aug 25, 2021 · Apply the chain rule over $$\sqrt {\frac {1- \sin (x)} {1+\sin (x)}}$$ And for differentiating $\frac {1- \sin (x)} {1+\sin (x)}$, you'll need to apply the quotient rule.
calculus - The chain rule and squared trig functions - Mathematics ...
Feb 15, 2012 · What I did try to do was rewrite it as $\frac {\cos x} {\sin x}\frac {\cos x} {\sin x}$ and then find the derivative of that but something went wrong with that and it does not produce …
Differentiating cosine squared of x - Mathematics Stack Exchange
Differentiating cosine squared of x Ask Question Asked 13 years, 1 month ago Modified 7 years, 11 months ago
What is the first derivative of $y= \sin^2 (\sqrt {x})$?
Mar 20, 2011 · I'm trying to find out what the graph of the function $y= \sin^2 (\sqrt {x})$ looks like. Can someone please help me?
Derivative of $\sin^2 (\sqrt {t})$ - Mathematics Stack Exchange
I need to find the derivative of $\sin^2 (\sqrt {t})$ which I believe have done but the answer seems to be more simplified and I don't know how to arrive to it.
calculus - The derivative of $ \tan x$ is $ \sec^2 x$. Why ...
Jul 24, 2019 · This is because we can think of the derivative as slope and previously saw that the slope was greatest near the asymptotes. Therefore, it is natural for $\sec^2 (x)$ to be the …